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Hmm... this might just be me being tired, but that sorta sounds right to me. I mean I've heard nothing but praise for the Core 2's temps, and considering my old AMD Barton is running at a steady 28-30 ish range on a stock cooler, that seems like it'd be acceptable.

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I was wondering why my computer is reporting such low temperatures for my CPU. The case sensor says it's at 29C (that sounds right) but the CPU one says 17-18C (that's really low)......

My CPU is an E6750 (2.66 ghz core 2 duo)

Depending on what software you are using, it could be reading it wrong (due to the 85C vs. 100C TJunction issue). Most likely you need to add 15C to each of the core temps which would give you around 33C which is reasonable considering your case temp is 29C.

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got SpeedFan to run....shows core0 and core1 running idle at 20-22C and i tried to run super pi (i know it's outdated) and the max i got was 30-31C.....i mean i knew the core 2 duo were cool but this is REALLY cool....sounds fishy to me... but then when i put my hand at the back of the computer the air coming out is really cool (can't check the heatsink because the case is closed)

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here's a screenshot of Core temp....same thing as Speedfan was giving me.....idle at 20-22 and full load in the low 30s.....im glad i have a really cool cpu but im kinda scared the reading is wrong.......but core temp says in the readme that it uses the temperature from the cpu itself.....im kinda confused

post-1419-1187556521.jpg

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here's a screenshot of Core temp....same thing as Speedfan was giving me.....idle at 20-22 and full load in the low 30s.....im glad i have a really cool cpu but im kinda scared the reading is wrong.......but core temp says in the readme that it uses the temperature from the cpu itself.....im kinda confused

If you look at the vcore it's running at 1.1V and if you look at others it's running at around 1.3V that's probrably why your temps are lower? You should look at intel's websites and look up the datasheet on the new intel procs it might shed some light. Rule of thumb, lower voltage=lower temps because P=I*V, P is power in watts(Joules/sec), I is current (Amps), and V is voltage.

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